Digital-Communication-题库.ppt

Slide Title is Palatino 36 pt.,First level bullet is Times New Roman 24 pt.and bold,Second level bullet is Times New Roman 20 pt.,Third level bullet is Times New Roman 18 pt.,Fourth level bullet is Times New Roman 16 pt.,Digital Communications Han Yu Bing,*,Slide Title is Palatino 36 pt.,First level bullet is Times New Roman 24 pt.and bold,Second level bullet is Times New Roman 20 pt.,Third level bullet is Times New Roman 18 pt.,Fourth level bullet is Times New Roman 16 pt.,Digital Communications Han Yu Bing,*,南京理工大学,电光学院通信工程系,Nanjing University of Science and Technology,Department of Communication Engineering,Slide Title is Palatino 36 pt.,First level bullet is Times New Roman 24 pt.and bold,Second level bullet is Times New Roman 20 pt.,Third level bullet is Times New Roman 18 pt.,Fourth level bullet is Times New Roman 16 pt.,2021/10/10,*,南京理工大学,电光学院通信工程系,Nanjing University of Science and Technology,Department of Communication Engineering,Slide Title is Palatino 36 pt.,First level bullet is Times New Roman 24 pt.and bold,Second level bullet is Times New Roman 20 pt.,Third level bullet is Times New Roman 18 pt.,Fourth level bullet is Times New Roman 16 pt.,2021/10/10,*,DigitalCommunications,HanYuBing,Tel：[phone],Office：TheEOEbuilding,RoomA311,2,3,4,5,6,Consider the three waveforms passing through an AWGN channel with power spectrum density of N0/2.,(1)Find the basis orthonormal functions for these signals;,(2)Use the basis functions to represent the three signals by vectors,and plot the signal space diagrams for these signals;,(3)Determine three likelihood functions,and show which probability of error is largest.,7,8,9,Signals of Non-linear Modulation with Memory,When m is even，the full response CPM signals phase states,When m is odd，the full response CPM signals phase states,In general case,when the CPM signals are M-ary modulation and partial response with duration LT,L is partial response waveform memory length;,M is the number of symbols,10,3.Assumed there are M signals s,m,(t),m=1,M to be transmitted with equal energy and probability.The dimensionality of theses signals are N,and the channel is AWGN channel with mean zero and variance N0/2.The received signal is r(t).,(1)Please plot the structure of the optimum receiver under the MAP criterion and briefly explain it.,11,12,13,14,15,16,17,18,Lowpass bandwidth W/2=1350Hz,19,20,f1,K=1,L=1,Eq.(9.4-439.4-47),21,22,23,24,25,26,Final Exam,Written and open-book exam,Time:To be determined,Place:To be determined,27,Thanks for your attention!,28,